Chemistry in Our Lives
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UNIFIED COUNCIL
A n I S O 9 0 0 1 : 2000 C e r t i f i e d O r g a n i s a t i o n
NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION - 2011
SOLUTIONS FOR CLASS : 9
Mathematics
1. (A)
∠AME = 80° = ∠BMN ∠MND = 180 0 − 80 0 = 100 0
6.
(D)
x x 3 − 3x 2 + 2x / x /
(
)
∴ remainder = 0 Quotient : x3 3x2 + 2x
In ∆MNQ, ∠MNQ + ∠NMP + ∠MQN = 1800 (or)
1 1 × 1000 + × 80 0 + ∠MQN = 180 2 2
7.
(D)
xy 1 1 1 =a⇒ = + x+y a x y
⇒ ∠MQN = 1800 − 900 = 900
2. (D)
1 1 1 1 = 1 +1 = + , b x z c y z
adding
1 1 2 1 1 2 1 + = + + = + a b x y z x c
y=a+
b x 1 b 5
1 = a − b and 5 = a − ⇒ a = 6 and b = 5
∴ a + b = 6 + 5 = 11
⇒
2 1 1 1 bc + ac − ab = + − = abc x a b c 2abc bc + ac − ab
8 Z 5 Y
⇒x=
8. (C)
3.
(B)
V = πr 2 h
X 2
x y = 2 + 8 + 5 = 15
= πa b
2
∴ X-U-Z-Y
9. 10.
(C) (C)
4.
(D)
Sum of n of observations = mn of O & m are added the sum = mn + 0 + m = m (n+1) No. of observations = n+2
∆ ABC ≈ ∆ DBE, ∆ DEF, ∆ ADF, ∆ ECF AB//CD//EF
⇒ ar • ∆AGB = 1 | |gm AEFB 2
[Q ∆AGBand| |gm AEFB
A E D G C B F
5.
(B)
m(n + 1) n+2 In a leap year, there are 366 days, i.e., 52 weeks and 2 days. ∴ New mean =
To have 53 sundays in the year, the extra day must be saturday, sunday or sunday, monday. so, required probability =
are on the same base and between same parallel lines AB and EF]
1 S ∴ar ∆AGB = | gm ABCD = . | 4 4
11. (B)
2 7
∠AQP = =
1 ∠AOP 2
1 × 750 = 37.50 2
(9_Class)_NAT_Solutions
website : www.unifiedcouncil.com
12.
(A)
a3 27 = 3 a1 1
a = a1
3
x2 = 10 4 : 3 is not the ratio of dimensions of the rectangle. 22. (C) OA = OB = AD= (1) (2)
27 3 = 1 1
13 = 6.5 cm 2
13.
(C)
Chicken = x goat = y x+y = 30 2x+4y = 84 chicken = 18,
5 12 = 6 cm, BC= = 2.5 cm 2 2
C B A D O
In ∆ADO, DO = 2.5 cm In ∆BCO CO = 6 cm Distance between the two chords CD = CO - OD = 6 - 2.5 = 3.5 cm. 23. (B) Q=5- 2 6
Sol. (1) & (2) we get goat...
A n I S O 9 0 0 1 : 2000 C e r t i f i e d O r g a n i s a t i o n
NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION - 2011
SOLUTIONS FOR CLASS : 9
Mathematics
1. (A)
∠AME = 80° = ∠BMN ∠MND = 180 0 − 80 0 = 100 0
6.
(D)
x x 3 − 3x 2 + 2x / x /
(
)
∴ remainder = 0 Quotient : x3 3x2 + 2x
In ∆MNQ, ∠MNQ + ∠NMP + ∠MQN = 1800 (or)
1 1 × 1000 + × 80 0 + ∠MQN = 180 2 2
7.
(D)
xy 1 1 1 =a⇒ = + x+y a x y
⇒ ∠MQN = 1800 − 900 = 900
2. (D)
1 1 1 1 = 1 +1 = + , b x z c y z
adding
1 1 2 1 1 2 1 + = + + = + a b x y z x c
y=a+
b x 1 b 5
1 = a − b and 5 = a − ⇒ a = 6 and b = 5
∴ a + b = 6 + 5 = 11
⇒
2 1 1 1 bc + ac − ab = + − = abc x a b c 2abc bc + ac − ab
8 Z 5 Y
⇒x=
8. (C)
3.
(B)
V = πr 2 h
X 2
x y = 2 + 8 + 5 = 15
= πa b
2
∴ X-U-Z-Y
9. 10.
(C) (C)
4.
(D)
Sum of n of observations = mn of O & m are added the sum = mn + 0 + m = m (n+1) No. of observations = n+2
∆ ABC ≈ ∆ DBE, ∆ DEF, ∆ ADF, ∆ ECF AB//CD//EF
⇒ ar • ∆AGB = 1 | |gm AEFB 2
[Q ∆AGBand| |gm AEFB
A E D G C B F
5.
(B)
m(n + 1) n+2 In a leap year, there are 366 days, i.e., 52 weeks and 2 days. ∴ New mean =
To have 53 sundays in the year, the extra day must be saturday, sunday or sunday, monday. so, required probability =
are on the same base and between same parallel lines AB and EF]
1 S ∴ar ∆AGB = | gm ABCD = . | 4 4
11. (B)
2 7
∠AQP = =
1 ∠AOP 2
1 × 750 = 37.50 2
(9_Class)_NAT_Solutions
website : www.unifiedcouncil.com
12.
(A)
a3 27 = 3 a1 1
a = a1
3
x2 = 10 4 : 3 is not the ratio of dimensions of the rectangle. 22. (C) OA = OB = AD= (1) (2)
27 3 = 1 1
13 = 6.5 cm 2
13.
(C)
Chicken = x goat = y x+y = 30 2x+4y = 84 chicken = 18,
5 12 = 6 cm, BC= = 2.5 cm 2 2
C B A D O
In ∆ADO, DO = 2.5 cm In ∆BCO CO = 6 cm Distance between the two chords CD = CO - OD = 6 - 2.5 = 3.5 cm. 23. (B) Q=5- 2 6
Sol. (1) & (2) we get goat...