A thin concavo-convex lens has two surfaces of radii of curvature R and 2R. The material of the lens has a refractive
index µ. When kept in air, the focal length of the lens :
(A) Will depend on the direction from which light is incident on it
(B*) Will be the same, irrespective of the direction from which light is incident on it
R
(C) Will be equal to µ 1
Sol.
From left to right
(D*) Will be equal to
R
µ 1
1
1
1
1 1
–
–
f L1 = (µ – 1) – R –2 R = (µ = 1) 2R R
µ
1
µ – 1
f L1 = – 2 R
From right to left
1
f L2 = (µ – 1)
=–
1
1
–
= (µ – 1)
2 R ( R )
convex
surface
2R
concave
surface
R
1 1
–
2R R
µ – 1
2R
1
1
2R
= f = – ( µ –1)
f L1
L2
Option (B) and (D) are correct.
2.
Sol.
An object is placed 10 cm away from a glass piece (n = 1.5) of length
20 cm bound by spherical surfaces of radii of curvature 10 cm. Find the
position of the final image formed after twice refractions.
Ans. [50 cm]
Refraction at first surface :
20 cm
air
air
B
object
A
10 cm ROC = 10cm
n = 1.5
ROC = 10cm
1.5
1
1.5 –1
– (–10) = (10) V1 = – 30 cm from A
V1
Refraction at second surface.
1
1.5
1 – 1.5
– (–50) = (–10) V2 = +50 cm from B
V2
Hence final image will be 50 cm from B.
3.
A concave mirror of radius R is kept on a horizontal table (figure). Water (refractive
index = ) is poured into it upto a height h. What should be distance of a point
object from surface along principal axis so that its final image is formed on itself.
Consider two cases.
(i) h 0
(ii) in terms of h
Page 1
( R h)
R
; (ii)
]
Ans. [(i)
Sol.
Object should appear to be at distance R from mirror.
µ(d) + h = R
if
Sol.
d=
h
h << R
4.
d
R–h
d=
µ
c
R
µ
A person's eye is at a height of 1.5 m. He stands infront of a 0.3 m long plane mirror which is 0.8 m above the ground,
The length of the image he sees of himself is :
(A) 1.5 m
(B) 1.0 m
(C) 0.8 m...